Question

Determine as massas moleculares relativas das seguinte moléculas:
° HNO₃
° C₈H₁₈
° C₆H₁₂O₆

Answer 1

HNO3 = (1x1) + (1 x 14) + (3 x 16) = 63g/mol  
C8H18 = (8 x 12)+(18 x 1)=114g/mol
C6H12O6 = (6 x 12) + (12 x 1) + (6 x 16) = 180g/mol

:.

Answer 2

a) $HNO_3 \\ H \to 1*1 = 1 \\ N \to 14 * 1 = 14 \\ O \to 16 * 3 = 48$

Massa molecular: $1 + 14 + 48= 63g/mol$

b) $C_8H_1_8 \\ C \to 12 * 8 = 96 \\ H \to 18 *1= 18$

Massa molecular: $96+18 = 114 g/mol$

c) $C_6H_1_2O_6 \\ C \to 12 * 6 = 72 \\ H \to 1 * 12 = 12 \\ O \to 16 * 6 =96$

Massa molecular: $180 g/mol$