Question

Determine as coordenadas do vértice da parábola que representa a função g(x)=-3(x-4)²+2.

Answer 1

$g(x)=-3( x^{2}-8x+16)+2= \\ \\ =-3 x^{2} +24x-48+2=-3 x^{2} +24x-46 \\ \\ x_{v}= \frac{-b}{2a}= \frac{-24}{-6}=4 \\ \\ y _{v}= \frac{-discriminante}{4a} \\ disc= 24^{2}-4.(-3).(-46)=24 \\ \\ y_{v}= \frac{-24}{-12}=2$