Question

Determinar o potencial no ponto P devido ás cargas puntiformes Q1, Q2 e Q3 cujos valores são 2¥C, 5¥C e -8¥C, respectivamente?

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Answer 1

Resposta:

Explicação:

Q₁ = 2 μC = 2.10⁻⁶ C                     d₁ = 3 cm = 3.10⁻² m

Q₂ = 5 μC = 5.10⁻⁶ C                    d₂ = 5 cm = 5.10⁻² m

Q₃ = -8 μC = -8.10⁻⁶ C                  d₃ = 4 cm = 4.10⁻² m

$V = k\frac{Q}{d}$

$V_{1} =9.10^9\frac{2.10^{-6}}{3.10^{-2}} \\\\V_{1} =\frac{18.10^{3}}{3.10^{-2}}\\\\V_{1} =6.10^{5}\:V$

$V_{2} =9.10^9\frac{5.10^{-6}}{5.10^{-2}} \\\\V_{2} =\frac{45.10^{3}}{5.10^{-2}}\\\\V_{2} =9.10^{5}\:V$

$V_{3} =9.10^9\frac{-8.10^{-6}}{4.10^{-2}} \\\\V_{3} =\frac{-72.10^{3}}{4.10^{-2}}\\\\V_{3} =-18.10^{5}\:V$

Potencial no ponto P

$V_{P} =V_{1} +V_{2} +V_{3} \\\\V_{P} =6.10^5+9.10^5+(-18.10^5)\\\\V_{P} =-3.10^5\:V$