Question

Dado log 2 = O,301 E LOG 3 = O,477 , calcule log 72

Answer 1

Resposta:

$log(2) = 0,301 \\ \\ log(3) = 0,477 \\ \\ log(72) = log( {2}^{3} \times {3}^{2} ) \\ \\ log( {2}^{3} ) + log( {3}^{2} ) = \\ \\ 3 log(2) + 2 log(3) = \\ \\ log(72) = 3 \times 0,301 + 2 \times 0,477 \\ \\ log(72) = 0,903 + 0,954 \\ \\ log(72) = 1,857$

Bons Estudos!