Question

dadas as funcoes y-x²-6x+8 encontre os valores do coeficiente a,b,c o valpr b² o valor de 4.a.c ∆=b²-4.a.c

Answer 1

y= x²-6x+8

x²-6x+8 = 0

a = 1

b = -6

c = 8

Δ = b² - 4 x a x c

Δ = (-6)² - 4 x 1 x 8

Δ = 36 - 32

Δ = 4

x = $\frac{-b+-\sqrt{4}}{2 a}$

x = $\frac{-(-6)+-2}{2$

x = $\frac{6 +-2}{2}$}

x1 = (6 +2)/2 -> 4

x2 = (6-2)/2 -> 2