Question

Dada as matrizes
A= 1 - 2 0
5 -4 3
B= - 3 6 12
9 - 6 15
Determine: - 4A - 2/3 Bt (B elevado no t) (B transposta)

Answer 1

$A=\begin{bmatrix}1&-2&0\\5&-4&3\end{bmatrix}$

$B=\begin{bmatrix}-3&6&12\\9&-6&15\end{bmatrix}$

$A-\frac{2}{3}B=\begin{bmatrix}1&-2&0\\5&-4&3\end{bmatrix}-\frac{2}{3}\begin{bmatrix}-3&6&12\\9&-6&15\end{bmatrix}$

$A-\frac{2}{3}B=\begin{bmatrix}1&-2&0\\5&-4&3\end{bmatrix}-\begin{bmatrix}-2&4&8\\6&-4&10\end{bmatrix}$

$A-\frac{2}{3}B=\begin{bmatrix}3&-6&-8\\-1&0&-7\end{bmatrix}$