Question

dada a funcaof(×)=3×+5,determine f(-3)+f(0)f(-2)

Answer 1

f(x) = 3*x + 5

f(-3) = 3*(-3) + 5 = -9 + 5 = -4

f(0) = 3*0 + 5 = 5

f(-2) = 3*(-2) + 5 = -6 + 5 = -1


f(-3) + f(0)*f(-2) = -4 + 5*(-1) = -4 -5 = -9

Answer 2

Olá,

f(x) = 3x+5

f(-3) = 3(-3)+5
f(-3) = -9+5
f(-3) = -4

f(0) = 3(0)+5
f(0) = 0+5
f(0) = 5

f(-2) = 3(-2)+5
f(-2) = -6+5
f(-2) = -1

f(-3)+f(0)f(-2) = -4+5(-1) = -4-5 = -9

Resposta:

-9