Question

Dada a função quadratica g (×)=-3×^2+2×-1 calcule

A)G (-2)=

B)G (-1)=

C)G (0)=

D)G (1)=

E)G (2)=

F)G (3)=


me ajuda por favor e pra hj ​

Answer 1

Explicação passo-a-passo:

g(x)=-3x^2+2x-1

g(-2)=-3.(-2)^2+2.(-2)-1

g(-2)=-3.4-4-1

g(-2)=-12-5

g(-2)=-17

g(-1)=-3.(-1)^2+2.(-1)-1

g(-1)=-3.1-2-1

g(-1)=-3-3

g(-1)=-6

g(0)=-3.0^2+2.0-1

g(0)=-1

g(1)=-3.(1)^2+2.1-1

g(1)=-3+2-1

g(1)=-1-1

g(1)=-2

g(2)=-3.(2)^2+2.2-1

g(2)=-3.4+4-1

g(2)=-12+3

g(2)=-9

g(3)=-3.(3)^2+2.3-1

g(3)=-3.9+6-1

g(3)=-27+5

g(3)=-22