Question

considere log2=a e log3=b, calcule?
a)log32
b)log8√27
c)log25

Answer 1

log 32 = log 2(elevado a 5 ) = 5. log 2= 5a

log 8raiz 27 = log 2³ x( 3³)elevado 1/2 =  2 x3/2 x log 2 x 3 =  6/2 x log 2 + log 3 = 3 x( a + b ) = 3a + 3b

 log 25 = log 5² = 2 x log 5 =log 5= log 10 : 2= log 10 - log 2 =  1 - a = 2 ( 1- a) = 2 - 2a