Question

Como resolver esta equação ×2-28×+192=0 obrigado!

Answer 1

$x^{2} - 28x + 192 = 0 \\ \\ a = 1, b = -28, c = 192 \\ \\ \Delta = b^{2} - 4 * a * c \\ \Delta = (-28)^{2} - 4 * 1 * 192 \\ \Delta = 784 - 768 \\ \Delta = 16 \\ \\ x = \frac{-b \pm \sqrt{\Delta} }{2*a} \\ \\ x = \frac{-(-28)\pm \sqrt{16} }{2} \\ \\ x = \frac{28\pm4}{2} \\ \\ x' = \frac{28+4}{2} = \frac{32}{2} = x' = 16 \\ \\ x'' = \frac{28 - 4}{2} = \frac{24}{2} = x'' = 12$