Question

como posso resolver essa equação ?

Answer 1

$\left|2x-1\right|=\dfrac{1}{3}\\ \\ 2x-1=\pm \dfrac{1}{3}\\ \\ 2x=\pm \dfrac{1}{3}+1\\ \\ 2x= \dfrac{\pm 1 +3}{3}\\ \\ x=\dfrac{\pm 1 + 3}{3}\cdot \dfrac{1}{2}\\ \\ x=\dfrac{\pm 1 + 3}{6}\\ \\ \begin{array}{rcl} x=\dfrac{1+3}{6}&\text{ ou }&x=\dfrac{-1+3}{6}\\ \\ x=\dfrac{4}{6}&\text{ ou }&x=\dfrac{2}{6} \end{array}\\ \\ \\ \boxed{\begin{array}{rcl} x=\dfrac{2}{3}&\text{ ou }&x=\dfrac{1}{3} \end{array}}$