Question

como eu resolvo essa equação 2x²-6x5=0?

Answer 1

$2x^2-6x+5=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-(-6)\pm\sqrt{(-6)^2-4(2)(5)}}{2(2)}\\\\x=\dfrac{6\pm\sqrt{36-40}}{4}\\\\x=\dfrac{6\pm\sqrt{-4}}{4}\\\\x=\dfrac{6\pm\sqrt{-4}}{4}\\\\x=\dfrac{6\pm\sqrt{4}\sqrt{-1}}{4}\\\\x=\dfrac{6\pm\sqrt{-4}}{4}\\\\x=\dfrac{6\pm\sqrt{4}\sqrt{-1}}{4}\\\\x=\dfrac{6\pm2i}{4}\\\\x=\dfrac{3\pm i}{2}\\\\x_1=\dfrac{3+i}{2}=\dfrac{3}{2}+\dfrac{1}{2}\ i\\\\x_2=\dfrac{3-i}{2}=\dfrac{3}{2}-\dfrac{1}{2}\ i$