Question

Como encotrar a equação de 2x2-12x+10 determinar as raizes eo vértice

Answer 1

Vamos là.

2x² - 12x + 10 = 0

delta

d = 144 - 80 = 64

as raízes

x1 = (12 + 8)/4 = 5

x2 = (12 - 8)/4 = 1

o vértice

Vx = -b/2a = 12/4 = 3

Vy = -d/4a = -64/8 = -8

Answer 2

Resposta:

Explicação passo a passo:

Para encontrar as raízes é preciso igualar a função a zero

2x² - 12x + 10 = 0

Raízes

a = 2; b = -12; c = 10

$\Delta=b^2-4ac\\\\\Delta = (-12)^2-4*2*10\\\\\Delta = 144- 80 = 64\\\\x' = \frac{-b+\sqrt{\Delta} }{2a} \\\\x' = \frac{-(-12)+\sqrt{64} }{2*2} \\\\x' = \frac{12+8 }{4} \\\\x' = \frac{20}{4} \\\\x' = 5\\\\x'' = \frac{-b-\sqrt{\Delta} }{2a} \\\\x'' = \frac{-(-12)-\sqrt{64} }{2*2} \\\\x'' = \frac{12-8 }{4} \\\\x'' = \frac{4}{4} \\\\x'' = 1$

                           Vértice

$x_v=\frac{-b}{2a}\\\\x_v=\frac{-(-12)}{2*2} \\\\x_v=\frac{12}{4} \\\\x_v=3$                                    $y_v=\frac{-\Delta}{4a} \\\\y_v=\frac{-64}{4*2} \\\\y_v=\frac{-64}{8} \\\\y_v=-8$