Question

Como calcular a raiz do delta 2x2 + 8x - 24 = 0

Answer 1

$2^{2} + 8x - 24 = 0$

Δ= $b^{2} - 4 . a . c$

Δ = $8^{2} - 4 . 2.-24$

Δ= $64 + 192$

Δ= 256

Fórmula de Bháskara.

±Δ

X1= $\frac{-8 + \sqrt{256} }{2.2}$

X1 = $\frac{-8 + 16 }{4}  = 2$

X1 = 2

X2= $\frac{-8 - 16}{4 }  = -6$

X2 = -6

S= {2, -6}