Question

com o exemplo dado no material acima resolva uma equação usando a fórmula de Bháskara.2ײ+4×-6=0
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Answer 1

$\boxed{\begin{array}{lr} 2x^2+4x-6=0 \end{array}}\\\\a=2\\b=4\\c=-6\\\\\boxed{\begin{array}{lr} \Delta=b^2-4.a.c\\\Delta=4^2-4.2.-6\\\Delta=64 \end{array}}$

$\boxed{\begin{array}{lr} x=\dfrac{-b\pm\sqrt{\Delta}}{2.2} \end{array}}\\\\\boxed{\begin{array}{lr} x=\dfrac{-4\pm8}{4} \end{array}}\\\\\boxed{\begin{array}{lr} x'=\dfrac{-4+8}{4}\ \ \ x'=\dfrac{4}{4}\ \ \ x'=1 \end{array}}\\\boxed{\begin{array}{lr} x''=\dfrac{-4-8}{4}\ \ \ x''=\dfrac{-12}{4} \ \ \ x''=-3\end{array}}\\\\\\\\S=\{-3,1\}$