Question

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128x^3y^8 + 36x^3y^7 = 4x^2you me ajudem pfv

Answer 1

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$(128x^3y^8+36x^3y^7)\div(4x^2y)= \\ \\ (128x^3y^8\div4x^2y)+(36x^3y^7\div4x^2y)= \\ \\ 32x^{3-2}y^{8-1}+9x^{3-2}y^{7-1}= \\ \\ 32xy^7+9xy^6$