Question

Bhaskara (3x + 1)^2 =(x +8)(x-3)

Answer 1

boa noite !!!!

$(3x + 1) {}^{2} = (x + 8)(x - 3) \\ \\ 9x {}^{2} + 6x + 1 = x {}^{2} - 3x + 8x - 24 \\ \\ 9x {}^{2} +6x + 1 = x {}^{2} + 5x - 24 \\ \\ 9x {}^{2} + 6x + 1 - x {}^{2} + 5x + 24 = 0 \\ \\ 8x {}^{2} + x + 25 = 0 \\ \\ x = \frac{1 + \sqrt{1 {}^{2} - 4 \times 8 \times 25} }{2 \times 8} \\ \\ x = \frac{ - 1 + \sqrt{1 - 800} }{16} \\ \\ x = \frac{ - 1 + \sqrt{ - 799} }{16} \\ \\ = x \: \: e \: \: r$

espero que eu tenha conseguido te ajudar princesa...