Question

b)(x + 3)². (x²- 4× + 4)​

Answer 1

${(x + 3)}^{2}( {x}^{2} - 4x + 4) =$

$({x}^{2} + 2 \times x \times 3 + {3}^{2} )( {x}^{2} - 4x + 4) =$

$( {x}^{2} + 6x + 9)( {x}^{2} - 4x + 4) =$

${x}^{2} ( {x}^{2} - 4x + 4) + 6x(x^{2} - 4x + 4) + 9( {x}^{2} - 4x + 4) =$

${x}^{4} - {4x}^{3} + {4x}^{2} + {6x}^{3} - {24x}^{2} + 24x + {9x}^{2} - 36x + 36 =$

${x}^{4} - {4x}^{3} + {6x}^{3} + {4x}^{2} - {24x}^{2} + {9x}^{2} + 24x - 36x + 36 =$

${x}^{4} + {2x}^{3} - {11x}^{2} - 12x + 36$

Answer 2

Oie, Td Bom?!

$= (x + 3) {}^{2} \: . \: (x {}^{2} - 4x + 4)$

$= (x {}^{2} + 2x \: . \: 3 + 3 {}^{2} ) \: . \: (x {}^{2} - 4x + 4)$

$= (x {}^{2} + 6x + 9) \: . \: (x {}^{2} - 4x + 4)$

$= x {}^{4} - 4x {}^{3} + 4x {}^{2} + 6x {}^{3} - 24x {}^{2} + 24x + 9x {}^{2} - 36x + 36$

$= x {}^{4} + 2x {}^{3} - 11x {}^{2} - 12x + 36$

Att. Makaveli1996