Question

Aplicando o teorema de Pitágoras, determine a medida x indicada no triângulo retângulo:

Answer 1

a) x²= 5²+12²

x²= 25+144

x²=169

x=$\sqrt{169\\}$

x=13

b) x²=2²+3²

x²=4+9

x²=13

x=$\sqrt{13}$

d)x²=6²+x²

x²=36+x²

x²+x²=36

2x²=36

x²=36/2

x²= 18

x=$\sqrt{18}$