Question

aplicando a fórmula de Bhaskara resolva
5x²+3x+5=0
X²-x-20=0
X²+2x-8=0
2x²-8x+8=0

Answer 1

a)5x²+3x+5=0
a=5 b=3 c=5

Δ=b²-4ac
Δ=3²-4×5×5
Δ=9-100
Δ= -91

b)x²-x-20=0
a=1 b=-1 c= -20

Δ=b²-4ac
Δ=(-1)²-4×1×(-20)
Δ=1+80
Δ=81

x= -b+-√Δ/2.a
x=-(-1)+√81/2.1

x'=1+9/2
x'=10/2
x'=5

x''=1-9/2
x"= -8/2
x''= -4

c)x²-2x-8=0
a=1 b=-2 c=-8

Δ=b²-4ac
Δ=(-2)²-4×1×(-8)
Δ=4+32
Δ=36

x= -b+-√Δ/2.a
x=-2+√36/2

x'=-2+6/2
x'=4/2
x'=2

x''=-2-6/2
x''=8/2
x''= -4

d)2x²-8x+8=0
a=2 b=-8 c=8

Δ=b²-4ac
Δ=(-8)²-4×2×8
Δ=64-64
Δ=0

x= -b+-√Δ/2.a
x= -(-8)+-√0/2×2

x'= 8+0/4
x'=2

x"=8-0/4
x"=2

Answer 2

Espero ter ajudado nessa atividade.