Question

alguem sabe essa questão 12 ? :/

Answer 1

$y= [1^{ \frac{1}{4} } + 2.1^ \frac{2}{3} - 0 ^\frac{1}{3} + 4^ \frac{1}{2} ] ^\frac{1}{2} \\ \\ y=[ \sqrt[4]{1} +2. \sqrt[3]{1^2} -0+ \sqrt{4} ]^ \frac{1}{2} \\ \\ y=[ 1+ 2.1+2]^ \frac{1}{2} \\ \\ y= 5^ \frac{1}{2} \\ y= \sqrt{5}$

Answer 2

$Resolu\c{c}\~ao\to \left\{\begin{array}{ccc}y = [1^{\frac{1}{4}+2*1^{\frac{2}{3}}-0^{\frac{1}{3}}+4^{\frac{1}{2}}]^{\frac{1}{2}}\\\\y = [\sqrt[4]{1}+2*\sqrt[3]{1^2}-\sqrt[3]{0}+\sqrt{4}]^{\frac{1}{2}}}\\\\y = [1+2*1-0+2]^{\frac{1}{2}}\\\\y = [1+2+2]^{\frac{1}{2}}\\\\\boxed{\boxed{y=\sqrt{5}}}\end{array}\right$

Espero ter ajudado. =^.^=