Question

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Answer 1

$V_A = \frac{k.q_0}{d}= \frac{9.10^{9}.3.10^{-6}}{1} = 27000 \ V \\ V_B = \frac{k.q_0}{d}= \frac{9.10^{9}.3.10^{-6}}{3} = 9000 \ V \\ W = -q(V_B - V_A) \\ W = -3.10^{-9}.(9000-27000) = 5,4.10^{-5} = 54.10^{-6} \ J \\ Resposta: \ e)$