Question

Alguem pode me ajudar?? Preciso de ajuda em logaritimo:

Dados log2=0,3010 e log3=0,4771, calcule log72

Answer 1

Boa noite Carol

log(72) = log(8*9) = log(8) + log(9)

log(8) = log(2^3) = 3log(2) = 3*0.3010 = 0.9030

log(9) = log(3^2) = 2log(3) = 2*0.4771 = 0.9542
log(72) = 0.9030 + 0.9542 = 1.8572
.

Answer 2

$\log 72=\log (3^{2}\cdot 2^{3})\\\\\log (3^{2}\cdot 2^{3})=2\log 3+3\log 2\\\\ \log (3^{2}\cdot 2^{3})=2\cdot 0,4771 + 3\cdot 0,3010\\\\ \log (3^{2}\cdot 2^{3})=0,9542 + 0,903\\\\\boxed{ \log 72 = 1,8572}$

Bons estudos!