Question

alguém pd mim ajudar pfv
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Answer 1

Resposta:

$a)\\ \\ x^{2} -4x+4\\ \\ coeficientes:\\ a=1\\ b=-4\\ c=4\\ \\ vertice(v)=\frac{-b}{2a} \\ \\ v=\frac{-(-4)}{2.1} =\frac{4}{2} =2$

$b)\\ \\ 3x^{2} -4x+2\\ \\ coeficientes:\\ a=3\\ b=-4\\ c=2\\ \\ vertice(v)=\frac{-b}{2a} \\ \\ v=\frac{-(-4)}{2.3} =\frac{4}{6} =\frac{2}{3}$

$c)\\ \\ 2x^{2} +4x+5\\ \\ coeficientes:\\ a=2\\ b=4\\ c=5\\ \\ vertice(v)=\frac{-b}{2a} \\ \\ v=\frac{-4}{2.2} =\frac{-4}{4} =-1$

$d)\\ \\ -2x^{2} +12x+7\\ \\ coeficientes:\\ a=-2\\ b=12\\ c=7\\ \\ vertice(v)=\frac{-b}{2a} \\ \\ v=\frac{-12}{2.(-2)} =\frac{-12}{-4} =3$