Question

alguem me ajuda pfv
a) 45 – { 4 . [( 9 . 12 – 14 . 7 ) : ( 15 – 5 . 2 )]}=


b) 20 : 4 + 3 . 2 – 15 : 3=


c) [ 25 – ( 18 : 3 )]. { 5 – [ 18 – ( 4 . 5 – 4 )]}=

Answer 1

Resposta:

A) 45-{4×[(9×12-14×7)÷(15-5×2)]}=

= 45-{4×[(108-98)÷(15-5×2)]}

= 45-{4×[(108-98)÷(15-10)]}

= 45-{4×[10÷5]}

= 45-{4×2}

= 45-8

= 37

B) 20÷4+3×2-15÷3=

= 5+3×2-15÷3

= 5+6-15÷3

= 5+6-5

= 11-5

= 6

C) [25-(18÷3)]×{5-[18-(4×5-4)]}=

= [25-6]×{5-[18-(20-4)]}

= 19×{5-[18-16]}

= 19×{5-[18-16]}

= 19×{5-2}

= 19×3

= 57

Espero ter ajudado!!

:)