Question

alguém me ajuda nessa aqui??

${8}^{5} \times {8}^{9}$

${x}^{ - 5} \times {x}^{ - 2} \times \frac{x {}^{12} } {x {}^{6} }$

$\frac{x}{ {x}^{6} }$

$( {x}^{ - 5} ) {}^{3}$

${y}^{ - 1} \times {y}^{ - 11} \times \frac{y {}^{15} }{y {}^{26} }$

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Answer 1

Resposta:

$8^{14}\\\frac{1}{x}\\\frac{1}{x^5}\\\frac{1}{x^{15}}\\\frac{1}{y^{23}}$

Explicação passo a passo:

$8^5.8^9=\\8^{5+9}=\\8^{14}\\\\x^{-5}.x^{-2}.\frac{x^{12}}{x^6}=\\x^{-5+(-2)}.x^{12-6}=\\x^{-7}.x^{6}=\\x^{-7+6}=\\x^{-1}=\\\frac{1}{x^1}=\\\frac{1}{x}\\\\\frac{x}{x^6}=\\\frac{x^1}{x^6}=\\x^{1-6}=\\x^{-5}=\\\frac{1}{x^5}\\\\(x^{-5})^3=\\x^{-5.3}=\\x^{-15}\\\frac{1}{x^{15}}\\\\y^{-1}.y^{-11}.\frac{y^{15}}{y^{26}}=\\y^{-1+(-11)}.\frac{y^{15}}{y^{26}}=\\y^{-12}.y^{15-26}=\\y^{-12}.y^{-11}=\\y^{-12+(-11)}=\\y^{-23}=\\\frac{1}{y^{23}}$