Question

Alguem me ajuda, ײ-8×+12=0

Answer 1

x^2-8x+12=0
delta=b^2-4ac
delta=(-8)^2-4.1.12
delta=64-48
delta=16
x=-b-/+ raiz de delta/2a
x=-(-8)-4/2.1
x=8-4/2
x=4/2
x=2
x=-(-8)+4/2.1
x=8+4/2
x=12/2
x=6
S={2, 6}

Answer 2

x² - 8x + 12 = 0
a = 1; b = - 8; c = 12

Δ = b² - 4ac
Δ = (-8)² - 4.1.12
Δ = 64 - 48
Δ = 16

x = - b +/- √Δ = - ( - 8) +/- √16
          2a              2.1

x = 8 + 4 = 12/2 = 6
        2

x = 8 - 4 = 4/2 = 2
        2

R.: x = 6 e x = 2