Question

ajuda aquiiiii..... please.

preciso do desenvolvimento e da resposta final. nao precisa de explicaçao.
$\\ \huge{ \frac{ \frac{2 {a}^{2} }{3a + bc} \sqrt{ \frac{1}{b + c} } }{ \frac{ {(b + 2b)}^{2} - 5c}{18ab} } }$
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Answer 1

$\\ \huge{ \frac{ \frac{2 {a}^{2} }{3a + bc} \sqrt{ \frac{1}{b + c} } }{ \frac{ {(b + 2b)}^{2} - 5c}{18ab} } } = \\ \\ \huge{ \frac{ \frac{2 {a}^{2} }{3a + bc} \times { \frac{1}{ \sqrt{b + c}} } }{ \frac{ {(3b)}^{2} - 5c}{18ab} } } = \\ \\ \frac{ \frac{2a^{2} }{(3a + bc) \sqrt{b + c} } }{ \frac{9b^{2} - 5c }{18ab} } =$

$\frac{36a^{3}b}{(3ab + bc) \sqrt{b + c(9 {b}^{2} - 5c) } } = \\ \\ \frac{36a^{3}b}{b \times (3a + c) \sqrt{b + c(9 {b}^{2} - 5c) } } = \\ \\ \frac{36a^{3}}{ (3a + c) \sqrt{b + c(9 {b}^{2} - 5c) } } =$

$\frac{36a^{3}b}{(27a {b}^{2} - 15ac + 9 {b}^{2}c - 5 {c}^{2} ) \sqrt{b + c}}$

att, BeatriceBaudelaire ღ