Question

a) X2-3x+2=0
o x e ao quadrado por favor que poder me ajuda com urgência as equação
b)x2-8x+15=0
c)x2-23x+12=0
d)x2+3x-4x=0
e) x2+6x+5=0
f)x2-5x+6=0
g) x2-16x+60=0
h)x2+x-12=0
i) x2-2x-8=0
valendo 8 ponto

Answer 1

a)x² - 3 x + 2 = 0
Δ = b² - 4.a.c
Δ = (-3)² - 4 . 1 . 2
Δ = 9 - 8
Δ = 1 ⇒ √ 1 = 1
x = - b + ou - 1/2
x´= -(-3) + 1 / 2
x´= 3 + 1 / 2
x´= 4/2
x´= 2 
x´´= 3 - 1 /2
x´´= 2/2
x´´= 1 
S = { 1 ; 2 }
b)x² - 8 x + 15 = 0
Δ = b² - 4.a.c
Δ = (-8)² - 4 . 1.15
Δ = 64 - 60
 Δ = 4 ⇒ √ 4 = 2
x = - b + ou - 2 / 2
x´= - (-8) + 2 / 2
x´= 8 + 2/2
x´= 10/2
x´= 5
x´´= 8 - 2 / 2
x´´= 6/2
x´´= 3 
S = {3 ; 5 }

c)x² - 23 x + 12 = 0
Δ = b² - 4.a.c
Δ = (-23)² - 4.1.12
Δ = 529 - 48
Δ = 481⇒ √ 481
x = - b + ou - √481 / 2
x´=-(-230 + √481 / 2 
x´= 230 + √481 / 2
x´= 115 + √481
x´´= 230 - √481 / 2
x´´= 115 - √481
S = {115 + √481 ; 115 - √481}

d)x² + 3 x - 4 = 0
Δ = b² - 4.a.c
Δ = 3² - 4 . 1 . - 4
Δ = 9 + 16
Δ = 25 ⇒ √ 25 = 5
x = - b + ou - 5 /2
x´= - 3 + 5 / 2
x´= 2/2
x´= 1
x´´= - 3 - 5 / 2
x´´= -8/2
x´´= - 4
S = {- 4 ; 1 }

e)x² + 6 x + 5 = 0
Δ = b² - 4.a.c
Δ = 6² - 4 . 1 . 5
Δ = 36 - 20
Δ = 16 ⇒ √16 = 4
x = - b + ou - 4/2
x´= - 6 + 4 / 2
x´= -2/2
x´= - 1
x´´= -6 - 4 / 2
x´´= -10/2
x´´ = - 5
S = {-1 ; - 5 }

f)x² - 5 x + 6 = 0
Δ = b² - 4.a.c
Δ (-5)² - 4.1.6
Δ = 25 - 24
Δ = 1 ⇒ √1 = 1
x = - b + ou - 1 / 2
x´= - (-5) + 1 / 2
x´= 5 + 1 / 2
x´= 6/2
x´= 3
x´´= 5 - 1/2
x´´= 4/2
x´´= 2
S = {2 ; 3 }

g)x² - 16 x + 60 = 0
Δ = b² - 4.a.c
Δ = (-16)² - 4.1.60
Δ = 256 - 240
Δ = 16 ⇒ √ 16 = 4
x=-b+ ou - 4/2
x´=-(-16) + 4/2
x´= 16 + 4 /2
x´= 20/2
x´= 10
x´´= 16 - 4 / 2
x´´= 12/2
x´´= 6 
S = {6 ; 10 }

h)x²  + x - 12 = 0
Δ = b² - 4.a.c
Δ = 1² - 4 . 1.-12
Δ = 1 + 48
Δ = 49 ⇒ √49 = 7
x = - b + ou - 7 / 2
x´= - 1 + 7 / 2
x´= 6/2
x´= 3
x´´= -1 - 7 / 2
x´´= -8/2
x´´= - 4
S = {-4 ; 3 }

i)x² - 2 x - 8 = 0
Δ = b² - 4.a.c
Δ = (-2)² - 4 . 1 . -8
Δ = 4 + 32
Δ = 36 ⇒√36 = 6
x = - b + ou - 6 / 2
x´= - (-2) + 6 / 2
x´= 2 + 6 / 2
x´= 8/2
x´= 4
x´´= 2 - 6 / 2
x´´ = -4/2
x´´ = - 2
S = {-2 ; 4 }