Question

a) (x+2) (x+3) =

b) (a-2) (a-7) =

c) (y+6) (y-6) =

d) (2x-5) (3x-2) =

e) (1-2x) (4+3x) =

f) (-x+4) (x+5) =

Answer 1

Resposta:

a) (x+2) (x+3)

${x}^{2} + 3x + 2x + 6 \\ {x}^{2} + 5x + 6$

b) (a-2) (a-7)

${a}^{2} - 7a - 2a + 14 \\ {a}^{2} - 9a + 14$

c) (y+6) (y-6)

${y}^{2} - 6y + 6y - 36 \\ {y}^{2} - 36$

d) (2x-5) (3x-2)

$6 {x}^{2} - 4x - 15x + 10 \\ 6 {x}^{2} - 19x + 10$

e) (1-2x) (4+3x) =

$4 + 3x - 8x - 6 {x}^{2} \\ - 6 {x}^{2} - 5x + 4$

f) (-x+4) (x+5)

$- {x}^{2} - 5x + 4x + 20 \\ - {x}^{2} - x + 20$