Question

A=
$( \sqrt{16})^{2} - ( - 3)^{2} =$
B=
$( - 1)^{0} - \sqrt{169} =$

a) A•B=
b) A²=
c) A•(B+B)=
d) A+A+B=
e) (B+B)-A=​

Answer 1

A)

4-9=-5

B)

1-13= - 12

-------------------

a) 60

b)25

C) - 5.(-12-12)

60+60=120

D) - 5+(-5)+(-12)=-22

E) - 12+(-12)-5=-29

Answer 2

Olá !

$A=( \sqrt{16})^{2} - ( - 3)^{2} \\ \\ </p><p>B=( - 1)^{0} - \sqrt{169}$

A= (4)^2-(9)

A=16-9

A=7

B= 1-13

B= -12

________________

a) A•B=7.(-12)= -84

b) A²= (7)^2= (7×7)= 49

c) A•(B+B)=7.(-12-12)= 7.(-24)=-168

d) A+A+B=7+7-12=14-12=2

e) (B+B)-A=(-12-12)-7= -24-7=-31

_______________

espero ter ajudado !

boa noite !