Question

a area de um trapezio é 39cm2 .A base maior mede 17 cm e a altura mede 3 m.Qual é a medida da base menor?​

Answer 1

$\textcolor{green}{A_{trapézio}=\frac{(B+b).h}{2}}$

$\textcolor{green}{39=\frac{(17+b).3}{2}} \\ \textcolor{green}{3(17+b)= 78} \\ \textcolor{green}{51 + 3b= 78} \\ \textcolor{green}{3b= 78 - 51}$

$\textcolor{green}{3b=27} \\ \textcolor{green}{b= \frac{27}{3} } \\ \textcolor{green}{b = 9cm\textcolor{blue}{\checkmark}}$