Question

a altura de um triângulo equilátero mede 4 cm . calcule a área desse triângulo.

Answer 1

Resposta:

Explicação passo-a-passo:

$h = \frac{l~\sqrt{3}}{2}\\\\4=\frac{l~\sqrt{3}}{2}\\\\l~\sqrt{3}=8\\\\l=\frac{8}{\sqrt{3}}$

$A = \frac{b*h}{2}\\\\A=\frac{4*\frac{8}{\sqrt{3}}}{2}\\\\A=\frac{32}{\sqrt{3}}*\frac{1}{2}\\\\A=\frac{16}{\sqrt{3}}~*~\frac{\sqrt{3}}{\sqrt{3}}\\\\A=16\sqrt{3}~cm^2$