Question

a) (47-2+5)÷(16÷8) =
b) [ 49-(6x6 - 15)+ 7 ] =
c) 54 + { 16-[(4 x 4 - 10)+3]} -
d) 15+{6+[(3×8-21)+2]}=
e) { 12+[8×(19-5)-10]}=
F) 6 x {3+ [(9x3-22)+2]} =
G) 76 + [ 15÷ (6÷2+2)+ 1] =
H) 4x{19+ [5+ (32÷4-6)]-10}=​

Answer 1

Resposta:

a) 25; b) 35; c) 61; d) 26; e) 114; f) 90; g) 80; h) 64

Explicação passo-a-passo:

a) $(47-2+5)\div(16\div8)=$

$(+50)\div(+2)=$

$25$

b) $49-(6\cdot6-15)+7=$

$49-(36-15)+7=$

$49-(+21)+7=$

$35$

c) $54+\{16-[(4\cdot4-10)+3]\}=$

$54+\{16-[(16-10)+3]\}=$

$54+\{16-[6+3]\}=$

$54+16-9=$

$61$

d) $15+\{6+[(3\cdot8-21)+2]\}=$

$15+\{6+[(24-21)+2]\}=$

$15+\{6+[3+2]\}=$

$15+\{6+5\}=$

$15+11=$

$26$

e) $12+[8\cdot(19-5)-10]=$

$12+[8\cdot14-10]=$

$12+[112-10]=$

$12+102=$

$114$

f) $6\cdot\{3+[(9\cdot3-22)+2]\}=$

$6\cdot\{3+[(27-22)+2]\}=$

$6\cdot\{3+[5+7]\}=$

$6\cdot15=$

$90$

g) $76+[15\div(6\div2+2)+1]=$

$76+[15\div(3+2)+1]=$

$76+[15\div5+1]=$

$76+[3+1]=$

$76+4=$

$80$

h) $4\cdot\{19+[5+(32\div4-6)]-10\}=$

$4\cdot\{19+[5+(8-6)-10\}=$

$4\cdot\{19-3\}=$

$4\cdot16=$

$64$