Question

a) 12× ²-50 =-2
b) 3ײ-60=0

Answer 1

Olá!!!

Resolução!!

São equações do 2° incompletas, não precisa de bhaskara ,

Veja :

a)

12x² - 50 = - 2
12x² - 50 + 2 = 0
12x² - 48 = 0
12x² = 48
x² = 48/12
x² = 4
x = ± √4
x = ± 2
x' = + 2
x" = - 2

S = { - 2, + 2 } → raízes

b)

3x² - 60 = 0
3x² = 60
x² = 60/3
x² = 20
x = ± √20

20 | 2
10 | 2
5 | 5
1

√20 → √2² • 5 → 2 • √5 → 2√5

x = ± √20
x = ± 2√5
x' = + 2√5
x" = - 2√5

S = { - 2√5, + 2√20 } → Raízes

Espero ter ajudado!!

Answer 2

Resposta:

$12x^2-50=-2\\\\12x^2-50+50=-2+50\\\\12x^2=48\\\\\frac{12x^2}{12}=\frac{48}{12}\\\\x^2=4\\\\x=\sqrt{4},\:x=-\sqrt{4}\\\\x=2<<\\\\\:x=-2<<$

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$3x^2-60=0\\\\3x^2-60+60=0+60\\\\3x^2=60\\\\\frac{3x^2}{3}=\frac{60}{3}\\\\x^2=20\\\\x=\sqrt{20},\:x=-\sqrt{20}\\\\x=2\sqrt{5}<<\\\\\:x=-2\sqrt{5}<<$

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