Question

7. Sabendo que A=9/4 B=1.5 C=2/5 Caucule
A: A.B²=?
B: (4A - 5C)²=
C: (B/3)³+C=
D: b² + 2/C - raiz quadrada de A=

Answer 1

Explicação passo-a-passo:

Calcule:

A) A×B²

B) (4A-5C)²

C) (B/3)³+C

D) B² + 2/C

$a) \: \frac{9}{4} \times( 1 \times 5)^{2} \\ \frac{9}{4} \times 25 = 225 \div 4 \\ \frac{225}{4} = 56.25 \\ b) \: (4a - 5c) ^{2} = 16a^{2} - 40ac^{2} + 25 {c}^{2} \\ 16 \times ( \frac{9}{4} )^{2} - 40 \times \frac{9}{4} \times (\frac{2}{5})^{2} \\ 16 \times \frac{81}{16} - 40 \times \frac{9}{4} \times \frac{4}{25} \\ \frac{1296}{16} - \frac{360}{4} \times \frac{4}{25} \\ \frac{1296}{16} - \frac{1440}{100} \\ \frac{32400 - 5760}{400} \\ 26640 \div 400 = 66.6$