Question

7. A soma dos termos da PG (1/3, 1/9, 1/27, 1/81, ...) é: a.1/4 b.1/2 c. 2/3 d. 1 e. 3/2

Answer 1

Resposta:b.1/2

Explicação passo-a-passo:

a1=1/3,q=a2/a1--->q=1/9/1/3--->q=3/9:3/3--->q=1/3,Sn=?

Sn=a1/1-q

Sn=1/3/1-1/3

Sn=1/3/(3/3-1/3)

Sn=1/3/2/3

Sn=3/6:3/3

Sn=1/2