Question

5 {x-3[x+4(x+12) + 10] - 20 } = 40
Me ajudeem , com contas pfvr

Answer 1

5{x-3[x+4+12x+10]=40
5{x-3[13x+14]-20=40
5{x+13x+14-3-20}=40
5{14x+14-32}=40
5{14x-9}=40
5+14x-9=40
14x-4=40
14x=40+4
14x=44
x=44/14
x3,142857...