Question

4) O vértice da função quadrática do f(x) = 2x² - 8x + 1, é: a) (2 , -7) b) (2 , 1) c) (-2 , -8) d) (1 , 4) e) (0 , 0)

Answer 1

Resposta:

f(x) = 2x² - 8x + 1

a = 2

b = -8

c = 1

o delta

d = 64 - 8 = 56

vértice

Vx = -b/2a = 8/4 = 2

Vy = -d/4a = -56/8 = -7

V(2, -7) (A)

Answer 2

Resposta:

Letra A

Explicação passo a passo:

f(x) = 2x² - 8x + 1

$x_V=-\frac{b}{2a} \\\\x_V=\frac{-(-8)}{2.2}\\\\x_V=\frac{8}{4} \\\\x_V=2\\\\y_V=f(2)\\\\y_V=2.2^2-8.2+1\\\\y_V=2.4-16+1\\\\y_V=8-16+1\\\\y_V=-7\\\\V(2,-7)$