Question

(3 elevado a 3) elevado a -1+(4 elevado a 4:4 elevado a 2)

Answer 1

$( 3^{3} )^{-1}+( \frac{ 4^{4} }{ 4^{2} } )= \\ \\ = 3^{-3} + 4^{4-2} = \\ \\ = \frac{1}{ 3^{3} } + 4^{2} = \\ \\ = \frac{1}{27} +16= \\ \\ = \frac{1+432}{27} = \\ \\ = \frac{433}{27}$