Question

3(2y-1)-2.(y-2)=-4(y-3)​

Answer 1

$3(2y-1)-2\cdot (y-2)=-4(y-3)$

$6y-3-2y+4=-4y+12$

$6y-2y+4y=12+3-4$

$8y=11$

$y=\frac{11}{8}$