Question

{2x-y=3 {x^2+y^2-3xy=x-2

Answer 1

 x² + 2y² + 3xy + x + y= 
x² + 2y² + 1+3xy + x + y-1= 
x² + 2x + 1+3xy + 2y² + y-1-x= 
(x + 1)²+y.(3x + 2y + 1)-(x+1)= 
(x + 1)(x+1-1)+y.(3x + 2y + 1)= 
x(x + 1)+y.(3x + 2y + 1)