Question

2) Dada a função f (x)=x^2-3x+2,cxomplete a tabela e construa o grafico.

x y=x^2-3x+2 (x,y)
−3
−2
−1
0
1
2
3

Answer 1

Explicação passo-a-passo:

f(-3) = 1.(-3)² - 3. (-3) + 2 = 1.9 + 9 + 2 = 20 (-3, 20)

f(-2) = 1.(-2)² - 3. (-2) + 2 = 1.4 + 6 + 2 = 12 (-2, 12)

f(-1) = 1.(-1)² - 3. (-1) + 2 = 1.1 + 3 + 2 = 6 (-1, 6)

f(0) = 1.(0)² - 3.0 + 2 = 1.0 + 0 + 2 = 2 (0, 2)

f(1) = 1.(1)² - 3.1 + 2 = 1.1 - 3 + 2 = 0 (1, 0)

f(2) = 1.(2)² - 3.2 + 2 = 1.4 - 6 + 2 = 0 (2, 0)

f(3) = 1.(3)² - 3.3 + 2 = 1.9 - 9 + 2 = 2 (3, 2)