Question

1) Use a fórmula de Bhaskara e encontre a solução para a equação x² - 16 = 0. *

S = { 4 }

S = { 0, -4 }

S = { 0, 4 }

S = { 4, -4 }


2 - Use a fórmula de Bhaskara e encontre a solução para a equação x² + 6x - 91 = 0. *


S = { 7, -13 }

S = { -7, 13 }

S = { 7, 13 }

S = { -7, -13 }

Outro:

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Answer 1

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$\sf{Por~ser~uma~equac_{\!\!,}\tilde{a}o~incompleta,o~ideal~\acute{e}~utilizar}\\\sf{outra~t\acute{e}cnica~contudo~vamos~utilizar~a~f\acute{o}rmula~"de~Bhaskara"}$

$\sf{1)}~\tt{x^2-16=0}\\\tt{a=1~~b=0~~c=-16}\\\tt{\Delta=b^2-4ac}\\\tt{\Delta=0^2-4\cdot1\cdot(-16)}\\\tt{\Delta=0+64}\\\tt{\Delta=64}\\\tt{x=\dfrac{-b\pm\sqrt{\Delta}}{2a}}\\\tt{x=\dfrac{0\pm\sqrt{64}}{2\cdot1}}\\\sf{x=\dfrac{0\pm8}{2}}\begin{cases}\tt{x_1=\dfrac{0+8}{2}=\dfrac{8}{2}=4}\\\tt{x_2=\dfrac{0-8}{2}=-\dfrac{8}{2}=-4}\end{cases}\\\huge\boxed{\boxed{\boxed{\boxed{\rm{S=\{-4,4\}}}}}}$

$\tt{2)}~\sf{x^2+6x-91=0}\\\sf{a=1~~b=6~~c=-91}\\\sf{\Delta=b^2-4ac}\\\sf{\Delta=6^2-4\cdot1\cdot(-91)}\\\sf{\Delta=36+364}\\\sf{\Delta=400}\\\sf{x=\dfrac{-b\pm\sqrt{\Delta}}{2a}}\\\sf{x=\dfrac{-6\pm\sqrt{400}}{2\cdot1}}\\\sf{x=\dfrac{-6\pm20}{2}}\begin{cases}\sf{x_1=\dfrac{-6+20}{2}=\dfrac{14}{2}=7}\\\sf{x_2=\dfrac{-6-20}{2}=-\dfrac{26}{2}=-13}\end{cases}\\\huge\boxed{\boxed{\boxed{\boxed{\rm{S=\{7,-13\}}}}}}$