Question

1)Resolva as seguintes equações

a)8(2x+6)=40
b)10(4x-2)=4(2x+8)
c)30-6(3x+9)=24+9(6x+15)
d)x-2(x-1)=4-3(x-2)​

Answer 1

Resposta:

$a) \: 8(2x + 6) = 40\\ 16x + 48 = 40 \\ 16x = 40 - 48 \\ 16x = - 8 \\ x = \frac{ - 8}{16}$

$c) \: 30 - 6(3x + 9) = 24 + 9(6x + 15) \\ 24(3x + 9 = 33(6x + 15) \\ 72x + 206 = 198 + 198 \\ 72x = 396 - 206 \\ 72x = 190 \\ x = \frac{190}{72}$

$b) \: 10(4x - 2) = 4(2x + 8) \\ 40x - 20 = 8x + 32 \\ 40x - 8x = 20 + 32 \\ 32x = 52 \\ x = \frac{52}{32}$