Question

1) Resolva as expressões numéricas abaixo:

a) 7-(1+3) =

b) 10 (2+5) +4=

b) 9-(5-1+2) =

d) (13-7)+8-1=

f) (10-4)-(9-8) +3=

h) 28+ [50- (24-2) -10] =

e) 15 (3+2)-6=

g) 50 [37 (15-8)]=

i)
20+ [13+ (10-6) + 4] =

i) 52-{12+ [15-(8-4)]} =

k) 25+ (12+ [2-(8-6) +2]} =

1) {[(18-3) + (7+5)-2]+5)-12=

n) 45+ (15-[(10-8)+(7-4)-3]-4}=

p) 38 (20-[22-(5+3)+(7-4+1)]) =

r) 25-[10+ (7-4)] =

m) 65-(30-[20-(10-1+6) + 1]} =

o) 40+ (50 [35-(25+5)-1])+7=

q) 26+(12-[(30-18)+(4-1)-6]-1)=

s) 32+ [10-(9-4)+8] =

t) 45-[12-4+(2+1)] =

u) 52+2³-2x (3+9)=

x) (72-1):3+2x5=

v) 62: 32+ 4 x 10-12 =

w) 42 10+ (23-5) =

y) 30 (2+1)²+ 2³ =

z) [4²+(5-3)³]: (9-7)³ =




me ajudem plmdss​

Answer 1

Resposta:

a) 7-4

3

b) 10 + 7 +4

17 + 4

21

c) 9 - 6

3

d) 6 + 8 - 1

13

e) 6- 2 + 3

7

f) 28 + [ 50 - 22 - 10]

28 + 28 -10

56 - 10

46

g) 15 + 5 -6

20 - 6

14

h) 50 + [37 + 7]

50 + 44

94